A racing car has a uniform acceleration of 4 ms.What distance will it cover in 10 secs,after its start.
Answers
Answered by
16
s = ut + 1/2 at^2
u=0
s= 1/2 at^2
s= 1/2(4))(100)
s=200
u=0
s= 1/2 at^2
s= 1/2(4))(100)
s=200
Anonymous:
Omg,thanks!
But how will we know which formula to use?I mean,will we get help from the units?
Answered by
15
u=0
v=?
a=4m/S↑2
T=10S
WE KNOW,
S=ut+½ at↑2
=0×10+½×4×10↑2
=0+2×100
=200
required distance=200m
v=?
a=4m/S↑2
T=10S
WE KNOW,
S=ut+½ at↑2
=0×10+½×4×10↑2
=0+2×100
=200
required distance=200m
Omg,thanks!
But how will we know which formula to use?I mean,will we get help from the units?
But how will we know which formula to use?I mean,will we get help from the units?
if i could meet u i would love to teach u brother my tecnics.but i would recommend u to learn the three equation of motion,and practice a lot of sums .this lesson matters a lot.
Thanks for the advice!
You must write first all the info given in question and after that write all the three laws... then find out which law you can use so that only one thing is unknown and rest are known... it will be easy for you then i think... i hope it help
obviously it will help me,einstein.
all the best buddy.
Merci beaucoup.
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