A racing car has a uniform acceleration of 4m/s^2. What distance will it cover in 10 sec after start?
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Answered by
16
Hi friend,
We know that,
S= ut+1/2at²
Initial velocity=0
S= 1/2×4×100
S= 200m.
Hope this helped you a little!!!
We know that,
S= ut+1/2at²
Initial velocity=0
S= 1/2×4×100
S= 200m.
Hope this helped you a little!!!
Answered by
6
10 points!
Brainly.in
What is your question?
Secondary SchoolPhysics 5+3 pts
A racing car has a uniform acceleration of 4m/s square .what distance will it cover in 10sec after start
Ask for details Follow Report by Abhi242rakesh 01.06.2017
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THE BRAINLIEST ANSWER!
gokujane
Gokujane Ambitious
here initial velocity=u
final velocity=v
acceleration=a
time=t
u=0
a=4
t=10
use the first equation of motion i.e -v=u+at
v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2
2*4*s=1600
s+1600/8=200m
Brainly.in
What is your question?
Secondary SchoolPhysics 5+3 pts
A racing car has a uniform acceleration of 4m/s square .what distance will it cover in 10sec after start
Ask for details Follow Report by Abhi242rakesh 01.06.2017
Advertisement
Answers
THE BRAINLIEST ANSWER!
gokujane
Gokujane Ambitious
here initial velocity=u
final velocity=v
acceleration=a
time=t
u=0
a=4
t=10
use the first equation of motion i.e -v=u+at
v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2
2*4*s=1600
s+1600/8=200m
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