Question

A racing car has a uniform acceleration of 4m/s^2.What will be the distance cover in 10 sec after the start???​

Answer 1

Answer:

Here initial velocity=u

final velocity=v

acceleration=a

time=t

u=0

a=4

t=10

use the first equation of motion i.e -v=u+at

v=0+40

v=40m/s

now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Explanation:

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Answer 2

Answer:

Hello ❤!!

Here, Initial Velocity =0

Time=10 seconds

Acceleration =4m/s^2

And,

distance=?

______________________

Now putting these values in the second equation of motion:

s=ut+1/2at^2

We get:

s=0×10+1/2×4×(10)^2

s=200m

Thus,The distance covered by the car in 10 seconds is 200 metres.

Hope this help u ☺