Question

x³+4x-3 by (x+5) in divide in each case check your answer using the relation 'dividend = divisor ×qutient× remainder​

Answer 1

Answer:

hey mate your answer is...

Step-by-step explanation:

p(x=-5)=x³+4x-3

p(x=-5)=(-5)^2+4(-5)-3

p(x=-5)=-25+20-3

p(x=-5)=-5-3

p(x=-5)=-8....

hope it's helps......