Question

A racing car has a uniform acceleration of 4m/s square the distance covered by the car in 10 सेकंड after the start

Answer 1

Answer:

1/2at^2=20 meter.........

Answer 2

Answer:

200 m

Explanation:

a = acceleration = 4m/s square

final velocity = v

initial velocity = u = 0 (as it starts from rest)

t = time = 10 sec

first equation of motion

v=u+at

v=0+4*10

v=40m/s

by third equation of motion

s= displacement

v square - u square = 2as

40^2 - 0^2 = 2*4*s

1600-0=8s

1600=8s

1600/8=s

200m= s