A racing car has a uniform acceleration of 4m/s square .what is the distance will it cover in 10sec after thr start
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Given,
a=4m/s² , t = 10s, u = 0 (initially it was at rest)
acc. to equations of motion --
S = ut + 1/2at²
Therefore,
Distance covered(S) = 0×10+(1/2×4×10×10)
S = 0+200 = 200 meters
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a=4m/s² , t = 10s, u = 0 (initially it was at rest)
acc. to equations of motion --
S = ut + 1/2at²
Therefore,
Distance covered(S) = 0×10+(1/2×4×10×10)
S = 0+200 = 200 meters
Mark as brainliest if this helps.....
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Refer https://brainly.in/question/4391450
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