Question

When a ball is thrown vertically upwards it goes through a distance of 19.6m find the initial velocity of ball and time taken to the highest point

Answer 1

We will use the following equation of motion :

Let g = 10m /s²

V² = U² - 2gs

Since it is projected upwards

V = 0

0 = u² - 2× 10 × 19.6

U² = 392

U = 19.80m / s (initial velocity)

Time taken to reach highest point :

S = ut - 0.5gt²

19.6 = 19.8 t - 5t²

Solving quadratic equation.

5t² - 19.8t + 19.6 = 0

Using quadratic formula :

u = {19.8 +/- √392 - 392} / 10

u = (19.8)/10 = 1.98 s

Answer 2

Answer:

Explanation:

We will use the following equation of motion :

Let g = 10m /s²

V² = U² - 2gs

Since it is projected upwards

V = 0

0 = u² - 2× 10 × 19.6

U² = 392

U = 19.80m / s (initial velocity)

Time taken to reach highest point :

S = ut - 0.5gt²

19.6 = 19.8 t - 5t²

Solving quadratic equation.

5t² - 19.8t + 19.6 = 0

Using quadratic formula :

u = {19.8 +/- √392 - 392} / 10

u = (19.8)/10 = 1.98 s