Question

A racing car has a uniform acceleration of 4m/s2.what distance will it cover in 10s after start?

Answer 1

S = ut + 0.5at^2
= 0.5at^2
= 0.5 * 4 * 10^2
= 200 m

Distance covered by racing car in first 10s after start is 200 m

Answer 2

Hi !

Initial velocity = u = 0
Time = t = 10 sec
Acceleration = a = 4 m/s²

Distance = S
S = ut + 1/2at²^2

= 0 + 1/2 × 4 × 10 × 10
= 200 metres

Distance traveled = 200 metres