Question

A racing car has a uniform acceleration of 4m/s².what distance will it cover in 10seconds after start ?​

Answer 1

Explanation:

s=ut+1/2 at^2

s=0x10+1/2x4x(10)^2

s=200 m

Answer 2

Answer:

Uniform acceleration (a)=4m/s^2

Initial velocity (u) = 0m/s

Time (t) =10sec

velocity (t) after 10 sec = u+a t = 0 m/s +4 m/s^2+×10 s = 40 m/s

We shall calculate the distance covered by all possible method.

Using Average velocity

Initial velocity u=0m/s

Final velocity v=40m/s

Average velocity=1\2(u+v)=1/2(0+40)=20m/s

time=10s

distance covered in 10s =av.vel. ×time=20m/s×10s=200m

Using the relation s =ut + 1/2 a t2

u+ 0m/s,a=4m/s2 ,t= 10 sec

Answer