Question

A racing car has a uniform acceleration of 4m/sec what distance it cover 10sec alter start

Answer 1

Here initial velocity=u
final velocity=v
acceleration=a
time=t

u=0
a=4
t=10
use the first equation of motion i.e -v=u+at

v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Answer 2

In it accerlation is 4m/s
Time 10sec.
So speed =4*10 = 40
Then distance is 40*10= 400