Question

integration of cos x^0 dx

Answer 1

the integration of cos xto the power 0 dx is x

Answer 2

Have two answer:

Therefore, Integration of  $cosx^{0} dx$ is $sin1.x+c$ or $\frac{\pi}{180} sin\frac{180}{\pi} x+c$

Step-by-step explanation:

Given,

Integration of  $cosx^{0} dx$

• If You mean  $x$to the power of zero:

$cosx^{0} =cos1$

Then,

  $\int sin1.dx$

$=sin1\int dx$

$=sin1.x+c$ (∵ $\int dx=x$ and $c$ is the constant )

So, Integration of  $cosx^{0} dx$ is $sin1.x+c$

• If you mean  x  degree then:

$x\,degree=\frac{180}{\pi}x\,radian$

$cosx^{0}=cos \frac{180}{\pi}x$

∴$\int cos \frac{180}{\pi}x.dx$

$=\frac{sin\frac{180}{\pi} x}{\frac{180}{\pi} } +c$

$=\frac{\pi}{180} sin\frac{180}{\pi} x+c$

So, Integration of  $cosx^{0} dx$ is  $\frac{\pi}{180} sin\frac{180}{\pi} x+c$