Question

A racing car has a uniform acceleration of 4ms-2 what distance will it cover in 20s after start

Answer 1

ANSWER :

Given :

▪ Initial velocity of racing car = zero

▪ Acceleration of car = 4m/s^2

▪ Time interval = 20s

To Find :

▪ Distance covered by car in the given interval of time.

Concept :

▪ Since acceleration is constant throughout the whole journey, we can apply equation of kinematics directly.

▪ Third equation of kinematics :

✴ S = ut + (1/2)at^2

Calculation :

⏭ S = ut + (1/2)at^2

⏭ S = (0×20) + (1/2)×4×(20)^2

⏭ S = 2×400

⏭ S = 800m

Answer 2

Answer:

The distance travelled by the racing car is

Explanation:

The initial velocity is zero as the far started from the rest =0

Acceleration=20m/s-²

Time=20s

Distance time relation;

s=ut+1/2at²

s=[ 0×20s ]+1/2[ 4×20²]

s= 0+1/2×4×400

s= 800m