Question

a racing car has a uniform acceleration of 4ms-2. what is the distance will it cover in 10 second after the start?​

Answer 1

Answer:

here initial velocity=u

final velocity=v

acceleration=a

time=t

u=0

a=4

t=10

use the first equation of motion i.e -v=u+at

v=0+40

v=40m/s

now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Please Please Mark My Answer As Brainliest Answer.

And Also Follow Me...✔️✔️

Thx.... ❤❤❤❤❤

Answer 2

Answer:

200 metres

Explanation:

Given :

• Uniform acceleration of the racing car = a = 4 m/s²

• Time taken = t = 10 seconds

• Initial velocity = u = 0 m/s (racing cars start from 0 m/s)

To find :

• Distance covered by the race car after its start

Using the second equation of motion :

S=ut+½×at²

S=0×10+½×4×10²

S=0+2×100

S=200 metres

The distance travelled by the racing car after start is equal to 200 metres