A racing car has a uniform acceleration of 4mt-2 what distances will it covers in 105 after start
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Given:
Initial velocity is: u=0
Acceleration is: a=4 ms
Time is: t=10 s
Using second equation of motion:
s= 0× 10 + ½ × 4 × 10²
s = 0 + 200
s = 200m
Therefore the distance covered is 200 m
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