A racing car has a uniform acceleration of 5m/s square. What distance will it cover in 20sec after starting from rest?
Answers
Answered by
212
a=5m/s2
t=20 sec
u=0
s=?
s=ut +1/2 at2
s=0+1/2 × 5 × 20×20
s= 0+5×10×20
s= 1000 km
thus, distance covered is 1000 km.
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MUSKAN
t=20 sec
u=0
s=?
s=ut +1/2 at2
s=0+1/2 × 5 × 20×20
s= 0+5×10×20
s= 1000 km
thus, distance covered is 1000 km.
I HOPE IT WILL HELP YOU
IF YOU LIKED IT PLZ RATE IT THE BRANIEST
KEEP SMILING
MUSKAN
Mus124:
thank you these little appreciation motivate me to help people. For future help please text me.
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Good....
Will you please solve few questions for me
define Linear ,circular ,translatory ,oscillatory, rotatory ,vibratory, simple harmonic motion
Answered by
93
Hi friend,
Here is your answer-
Units-
a=acceleration
t=time
u=initial velocity
s=distance
Here we go-
a=5m/s
t=20s
u=0
s=?
To find s, we will apply the formula - ut+1/2 at^2
s=ut+1/2 at^2
s=0*20+1/2 5*20*20
s=0+1/2 5*400
=1*5*200
=1000km
Hence, the distance (s) travelled is 1,000km.
Here is your answer-
Units-
a=acceleration
t=time
u=initial velocity
s=distance
Here we go-
a=5m/s
t=20s
u=0
s=?
To find s, we will apply the formula - ut+1/2 at^2
s=ut+1/2 at^2
s=0*20+1/2 5*20*20
s=0+1/2 5*400
=1*5*200
=1000km
Hence, the distance (s) travelled is 1,000km.
Nice
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