A racing car has a uniform acceleration of 6m/s. what distance will it cover 12s after the start
Answers
Answered by
1
Explanation:
if it runs with uniform motion, then
in 1 second,6m
in 12sec, 6m×12=72m
Answered by
13
Final velocity (v) = 72m/s
Explanation:
Question-
A racing car has a uniform acceleration of 6m/s² . What distance will it cover 12s after the start?
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Given Information -
- Initial velocity (u) = 0m/s
- Acceleration(a) = 6m/s²
- Time (t) = 12 secs.
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Required Solution-
- Final velocity (v)
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Solution -
What to do?
To find the final velocity with the given information, we'll follow the formula of Velocity Time Relation and will replace the value with the formula to attain our required solution.
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Formula -
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Answer -
[Replacing values]
ㅤ v = u+at
ㅤv= 0+(6×12)
ㅤv= 0+72
ㅤv= 72
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ㅤSo, final velocity (v) is 72 m/s.
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