Question

a racing car has a uniform acceleration of 8m/s.What will it cover 12s after start ​

Answer 1

Step-by-step explanation:

Uniform acceleration of the racing car = 8 m/s

Initial velocity of the racing car = 0 m/s

Time taken by the racing car = 12 sec

To Find :-

Distance covered by the racing car.

Analysis :-

Here we are given with the acceleration, initial velocity and the time taken by the racing car.

Using the second equation of motion, substitute the given values in the questions and find the distance covered accordingly.

Solution :-

We know that,

s = Distance

u = Final velocity

t = Time

a = Acceleration

Using the formula,

\underline{\boxed{\sf Second \ equation \ of \ motion=s=ut+\dfrac{1}{2} at^2}}

Second equation of motion=s=ut+

2

1

at

2

Given that,

Initial velocity (u) = 0 m/s

Time (t) = 12 sec

Acceleration (a) = 8 m/s

Substituting their values,

\sf s=0 \times 12 + \dfrac{1}{2} \times 8 \times 12^2s=0×12+

2

1

×8×12

2

\sf s=\dfrac{1}{2} \times 8 \times 144s=

2

1

×8×144

\sf s=\dfrac{8 \times 144}{2}s=

2

8×144

\sf s=\dfrac{1152}{2}s=

2

1152

\sf s=576 \ ms=576 m

Therefore, the distance covered by the racing car 12 seconds after the start is 576 m.