a racing car has a uniform accerlation of 4m s-2.what distance will it cover in 10second after start?
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u=initial velocity, a=acceleration, t= time, s= distance covered. .....
u =0m/s (since it is starting from rest)
a = 4m/s^2
t=10 seconds
s=? (s = distance covered )
s=ut+1/2 at ^2( 2nd equation of motion)
s=0×10+1/2×4×10×10
s=0+400/2
s=400/2
s=200 mts
HENCE THE CAR COVERS 200 METRES AFTER 10 AFTER START
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________________________________
HERE IS YOUR ANSWER ✌✌✌
_______________________________
ANSWER ☺☺☺
u=initial velocity, a=acceleration, t= time, s= distance covered. .....
u =0m/s (since it is starting from rest)
a = 4m/s^2
t=10 seconds
s=? (s = distance covered )
s=ut+1/2 at ^2( 2nd equation of motion)
s=0×10+1/2×4×10×10
s=0+400/2
s=400/2
s=200 mts
HENCE THE CAR COVERS 200 METRES AFTER 10 AFTER START
___________________________________
HOPE IT HELPS U ☺☺☺✌✌✌
___________________________________
PLEASE MARK ME BRAINLIEST ⭐⭐⭐✔✔✔
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