Question

A racing car has a uniform Accleration of 4 m ${s} ^{-2}$.
What distance will it cover in 10 s after start? ​

Answer 1

Explanation:

Here initial velocity=u

final velocity=v

acceleration=a

time=t

u=0

a=4

t=10

use the first equation of motion i.e -v=u+at

v=0+40

v=40m/s

now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Answer 2

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$\huge \star {\underline {{SOLUTION }}}$

Given,

Acceleration, a=4 m [tex] {s} ^{-2}[/tex]

Initial velocity, u=0

Time, t=10 s

Therefore, distance covered s=?

We know that, s= ut + 1/2at^2

S= 0 x 10 + 1/2 x 4 x (10)^2

S=1/2 x 4 x 100

S = 2 x 100m=200m

Thus the racing car will cover a distance of 200 m after start in 10 s with the given Accleration.