A racing car has an acceleration of 4m/s^2. What distance will it cover in 20 seconds after start?
Answers
Answered by
7
we will use the formula:-
s=ut+1/2 at2
s=0x20+1/2x4x20x20
s=o+1/2x4x400
s=800m
i hope it is correct
s=ut+1/2 at2
s=0x20+1/2x4x20x20
s=o+1/2x4x400
s=800m
i hope it is correct
satyam91:
Thanks
Answered by
2
here
u=0
a=4 m/s^2
t=20 sec
by using
s = ut+1/2at^2
s = 0+1/2×4m/s²×20 s
=40 m
u=0
a=4 m/s^2
t=20 sec
by using
s = ut+1/2at^2
s = 0+1/2×4m/s²×20 s
=40 m
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