Question

A racing car has an acceleration of 4m/s what distance will it cover in 20 seconds after start ? with method​

Answer 1

Explanation:

acceleration = 4 m/s^2

time= 20 seconds

we know,

acceleration = velocity/time

velocity= acc. × time

v= 4× 20

v= 80 m/s

we also know,

velocity = displacement/time

displacement= velocity ×time

s= 80×20

s= 1600 metre

ANSWER =1600

Answer 2

$\star\:\:\:\bf\large\underline\blue{Given:—}$

☞︎︎︎ Initial velocity of a car, u = 0 (at rest)

☞︎︎︎ Acceleration, a = 4 m/s²

☞︎︎︎ Time, t = 20 seconds

$\star\:\:\:\bf\large\underline\blue{To\:find:—}$

Distance travelled by car = ?

$\star\:\:\:\bf\large\underline\blue{Solution:—}$

As per second law of motion ,

$\boxed{\bf{\red{Formula:—S=ut+1/2at²}}}$

Here S means distance travelled by car after 20 seconds

➪ S = 0 + 1/2 × 4 × (20)²

➪ S = 800 m

Therefore, distance travelled by car after 10 s = 800 m

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