A racing car has an acceleration of 5_m /52 what distance will it covers in 205 after starting from rest
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Answered by
1
given here
a=5
t=205s
u=0
then s=?
we know that
S=ut +1/2at*t
= 0*205+1/2*5*205*205
=105062.5m
=105.0625km
IF YOU ARE SATISFIED WITH MY ANSWER FOLLOW ME
a=5
t=205s
u=0
then s=?
we know that
S=ut +1/2at*t
= 0*205+1/2*5*205*205
=105062.5m
=105.0625km
IF YOU ARE SATISFIED WITH MY ANSWER FOLLOW ME
Gurpreetb:
u need to find answer in metres i think all the quantities are in SI units
my answer is on t =205s
thats fine bt time is in sec. and acceleration is in m/s^2 so how ur answer would be in km
if your question t=20s then answer will be 1000m
sorry sorry my mistake
above km i have. also answered in m see again
i commit i haven't seen it
its fine
thank you
welcome sir
Answered by
0
s=ut+1/2at^2
s=0+1/2(5×400) {u=0,a=5,t=20 therefore t^2=400
s=1/2(2000)
s=1000m
s=0+1/2(5×400) {u=0,a=5,t=20 therefore t^2=400
s=1/2(2000)
s=1000m
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