A racing car has uniform acceleration of 4m/s2. How much distance will it cover in 10s after the start
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gokujane
Gokujane Ambitious
here initial velocity=u
final velocity=v
acceleration=a
time=t
u=0
a=4
t=10
use the first equation of motion i.e -v=u+at
v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2
2*4*s=1600
s+1600/8=200m
ayusmaan12:
your answer is correct
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