Question

A racing car initially at rest, accelerates at a uniform rate of 5.5 m/s² for 10 s. Calculate (i) the distance covered by the racing car from start, and (ii) the final velocity in km/h.​

Answer 1

275 m will be the distance covered by the car

198 Km/h  will be the final velocity

Explanation:

S= Ut + 1/2 a t ²

as initially the car was at rest U = 0

S = 1/2 ** 5.5 * 10 * 10

   = 550/2

   = 275 m .  

(ii) final velocity  =

V= u + at

u = 0

V=  5.5 * 10

  = 55 m/s

  = or  198 Km/h

Answer 2

Answer:

We know that:

$\tt{s = ut + \frac{1}{2} at^{2}}$

Given that:

Acceleration = 5.5 m/s^2

Time = 10 s

Initial Velocity (u) = 0 m/s

s = (0)(10) + (1/2)(5.5)(10)(10)

s = 0 + 275

s = 275 m

Final Velocity (v):

v = u + at

v = 0 + (5.5)(10)

v = 55 m/s

in km/h:

55×18/5 = 11 × 18

=> 198 km/h

Hope it Helps!!!!