Question

A racing car is moving with an uniform acceleration of 4m/s how much distance will its cover 10 s after it starts moving from rest

Answer 1

we already know

s=ut+1/2at^2

s=distance

u=0(starts from rest)

t=10,,a=4

s=1/2×4×10×10

s=200 m

hope it helps

Answer 2

$\large\bf\:Answer:$

Given:

 Initial velcoity=u= 0 m/s

Time= t=10 sec

uniform acceleration=a=4m/s²

Distance =s=?

From second equation of motion:

S=ut+1/2at²

=0x10+1/2x4x[10]²

=2x100

=200m.

∴$<b>$Distance it will cover in 10sec after start is 200m