Question

a radio station tower was built in two sections A and b , is supported by wires at point o . distance between the point o and base of tower is 36 m and from point o the angle of elevation to the top of section b is 30 ^ 2 and for a is 45^2 . what is the height of section b​

Answer 1

We will take two trianlge to solve this question.

Step-by-step explanation:

In ∆AOD,

tan30°=AD/OD

AD=36/✓3=20.784m{It is the height of section B}

Now in trianlge BOD,

tan45°=BD/OD

So,BD=OD(as tan45°=1)

This,AB=BD-AD=36-20.784=15.216m{It is the height of section A}

Answer 2

Answer:

12 root 3 is the answer. height of section a is 12(3-root3)