Physics, asked by lephongkonyak92, 1 month ago

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 year.Find the time,in year, after which one-fourth of the material remains.

Answers

Answered by aanchalporte200611

Answer:

A radioactive material decays by simultaneous emission of two particles with respective half-lives 1620 and 810 years. The time, in years, after which one-fourth of the material remains is: A. 1080

Previous Question

Next Question

Similar questions

Science, 15 days ago

in a single movable pulley a load of 500N is lifted by applying 300N effort.calculate MA,VR and effeciency...

English, 15 days ago

essay in unemployment in 1000 word no spam internet copy wala ni chalega guys..

History, 15 days ago

Analyse the circumstances which provided Mughals to rule over India...

English, 1 month ago

write the correct answer from the given alternatives. ____ is the sun...

Math, 1 month ago

(D^2 - 1)y = xe^x + cos^2 x...

English, 9 months ago

1.Suggest why it is better to eat fresh fruit and vegetables as a source of vitamin C rather than to take tablets. 2.Junk food is thought to have caused many dietary problems. Explain what junk food is and explain in detail the problems it has caused.

English, 9 months ago

a group of sheep collective nouns ...

Chemistry, 9 months ago

what is the volume of a 3.2 gm gas element in S.T.P?

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 year.Find the time,in year, after which one-fourth of the material remains.​

Answers

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 year.Find the time,in year, after which one-fourth of the material remains.