A radioactive substance contains 10000 nuclei
and its half-life period is 20 days. The number of
nuclei present at the end of 10 days is
(a) 7070 (b) 9000
(c) 8000 (d) 7500
Answers
Answered by
4
the answer is (b) 9000 if it is present in the nuclei region of the cell..... if the period of 20 days ...ends in tge 10 days
Answered by
1
Option d is correct,because in 10 days only half of half(quarter of total ) nuclei are decomposed. So remaining nuclei = 10000-(10000)/4= 7500
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