A radioactive substance decays so that 3% of its initial nuclei remain after 60 seconds. The
half life period of the substance is nearly
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Answer:
1000 seconds
Explanation:
For 1% = 60/3
= 20seconds
For 100% = 20×100
= 2000seconds
Therefore for 50 % ( half life period)
= 2000 ÷ 50
= 1000 seconds
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