Physics, asked by abhi99chauhan, 1 year ago

A radioactive substance of 1 g is reduced to 2.1 mg in 5 years by alpha decay. Calculate the half-life of the substance.

Answers

Answered by shrey1998vp56bg9
0
yearsnotice that the number of nuclei is proportional to the mass in a given sample
Answered by BatteringRam
0

Answer: The half-life of a substance is 0.561 years.

Explanation:

All radioactive decay processes follow first-order reactions.

The integrated rate law equation for first-order kinetics:

k=\frac{2.303}{t}\log \frac{a}{a-x}      ...(1)

Given values:

a = initial concentration of reactant = 1 g

a - x = concentration of reactant left after time 't'  = 2.1 mg = 0.0021 g      (Conversion factor: 1 g = 1000 mg)

t = time period = 5 yrs

Putting values in equation 1:

k=\frac{2.303}{5yr}\log (\frac{1}{0.0021})\\\\k=1.2334 yr^{-1}

Calculating rate constant for first order reaction using half life:

t_{1/2}=\frac{0.693}{k}     ...(2)

t_{1/2} = half life period

k = rate constant = 1.2334 yr^{-1}

Putting values in equation 2:

t_{1/2}=\frac{0.693}{1.2334yr^{-1}}\\\\t_{1/2}=0.561yr

Hence, the half-life of a substance is 0.561 years.

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