Question

A radioactive substance undergoes the following transformation 6 alpha followed by 4 beta such that the atomic number and atomic mass number of the final product so obtained is 84 and 216 respectively. Find the atomic number and atomic mass number of the original substance.

Answer 1

Answer:

$\huge{\underline{\mathtt{\red{❥A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$