solve the following system of equations y+z=5 and y²+2z²=17
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Answer:
D=
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1
1
1
1
2
3
1
2
λ
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=
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1
−1
1
1
0
3
1
0
λ
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=1.(λ−3)
D
1
=
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5
6
μ
1
2
3
1
2
λ
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=
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5
−4
μ
1
0
3
1
0
λ
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=4.(λ−3)
D
2
=
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1
1
1
5
6
μ
1
2
λ
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=
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1
0
0
5
1
μ−6
1
1
λ−2
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=λ−2−μ+6=λ−μ+4
D
3
=
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1
1
1
1
2
3
5
6
μ
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=
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1
0
0
1
1
1
5
1
μ−6
∣
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=μ−6−1=μ−7
For infinitely many solution
D=0,D
1
=0,D
2
=0,D
3
=0
λ=3,λ=3,λ−μ=−4,μ=7
λ=3 and μ=7
x+y+z=5.....(i)
x+2y+2z=6...(ii)
x+3y+3z=7....(iii)
from (i) and (ii) y+z=1⇒x=4 which stisfy (iii) equation hence there are infinite number of solution λ+μ=10
explanation
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