A raffle ticket consist of 20 prizes. The first prize is 25000 pesos and each successive prize is 500 pesos less than the preceding prize. What is the total prize of the raffle ticket?
Answers
Answer:
I think the answer will be 3, 32, 000 pesos
Step-by-step explanation:
Please mark me as brainliest and please follow me
Hope u like my answer
Concept:
The difference between any two consecutive integers in an arithmetic progression (AP) sequence of numbers is always the same amount. It also goes by the name Arithmetic Sequence. For instance, the natural number sequence 1, 2, 3, 4, 5, 6,... is an example of an arithmetic progression. It has a common difference of 1 between two succeeding terms (let's say 1 and 2). (2 -1). We can see that the common difference between two subsequent words will be equal to 2 in both the case of odd and even numbers.
NO. OF TERMS,
Tₙ= a+(n-1)d
Sum of terms,
Sₙ = n/2(2a + (n-1)d)
Given:
A raffle ticket consist of 20 prizes. The first prize is 25000 pesos and each successive prize is 500 pesos less than the preceding prize.
Find:
What is the total prize of the raffle ticket?
Solution:
Since we see that, the amount of prize is decreasing by 500, so its a arithmetic progression.
a=25000
n=20
d=-500
Sₙ = n/2(2a+(n-1)d)
S₂₀= 20/2 (2 x 25000 +(20-1)(-500))
= 10 (50000- 19 x 500)
= 10 (40500)
= 405000 pesos
Therefore, the total prize of the raffle ticket is 405000 pesos
#SPJ3