A railroad car of mass M is at rest on frictionless rails when a man of mass m starts moving on the car towards the engine. If the car recoils the speed v backwards on the rails, with what velocity is the man approaching the engine?
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mass of car = M.
mass of man = m.
Initially velocity of car = u = 0 m/s.
velocity of man = u1 m/s.
speed required by a car= v
by the law of CONSERVATION OF LINEAR MOMENTUM
mu1 + Mu = (m+M)V
mu = (m+M)v
or,
u(initial velocity of man) = [(m+M)V]/u
=v[1+M/m]
mass of man = m.
Initially velocity of car = u = 0 m/s.
velocity of man = u1 m/s.
speed required by a car= v
by the law of CONSERVATION OF LINEAR MOMENTUM
mu1 + Mu = (m+M)V
mu = (m+M)v
or,
u(initial velocity of man) = [(m+M)V]/u
=v[1+M/m]
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2
Explanation:
A railrod car of ma sM is at rest o frictionless rails when a man of mass m starts movng on the casr towards the engine. The car recoils with a speed v backward on the rails. Let the mass moving with a velocity x w.r.t the engine. ∴ The velocity of the mass w.r.t earth is (x-v) towards right.
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