a railway car of mass 20 tones mass with an initial speed of 54 km per hour on applying break a constant negative according of 0.3 M per second square is produced the first what is the breaking force acting on car
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Given,
mass(m) of the railway car=20 tonnes or 2000kg
Initial velocity(u)=54km h⁻¹ or 15m/s
0.3 m/s²(breaking negative),acceleration
As we know,
F=d²r/dt² or ma
F=2000kg x 0.3ms⁻²
F=600N
mass(m) of the railway car=20 tonnes or 2000kg
Initial velocity(u)=54km h⁻¹ or 15m/s
0.3 m/s²(breaking negative),acceleration
As we know,
F=d²r/dt² or ma
F=2000kg x 0.3ms⁻²
F=600N
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