Question

A railway engine of mass 12000 kg is

moving at a constant speed of 5 m/s up

an inclined plane of 15°. Calculate the

power of the engine. Given g = 9.8 m/s² .​

Answer 1

Answer:

Hi.

Hope it helps

using the formula Power = FV

I.e force * velocity

Force= mg

Answer 2

Answer:

The power of the engine is 1.52 w.

Explanation:

Step 1: Given,

railway engine of mass=12000 kg

$g=g=9.8 \mathrm{~m} \cdot \mathrm{s}^{-2}$

Determine the frictional force on the total mass of the train in units of newton. The power is the product of force and velocity.

Step 2: Formula used:

Power, $P=F v$

where. $F$ is the force and $v$ is the velocity.

If work is done faster, power is higher. If work is done slower, power is smaller. Since work is force times displacement, and velocity is displacement over time (v=d/t), power equals force times velocity

Step 3:

$\begin{aligned}F & =m g \sin \theta \\& =12000 \times 9.8 \times \sin 15 \\& =30437.1 \mathrm{~N} \\\text { Power } & =F \times v \\& =30437.1 \times 5 \\& =1.52 \times 10^5 \mathrm{~W}\end{aligned}$

Hence, The power of the engine is 1.52 w.

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