Question

a raindrop of diameter4mm is about to fall on the ground calclulate inside the raindrop [surface tension of water T=0.072n/m,atmospheric pressure=1.013×100000n/m×m​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Pressure inside the raindrop is 1.01372 * 10⁵ Pa

Explanation:

Given,

A raindrop of diameter 4mm is about to fall on the groud.

To calculate: The pressure inside the raindrop.

Solution:

Surface Tesion = 0.072 N/m.

and, Atmospheric pressure is obviously 1.013 * 10⁻⁵ N / m²

We have been given diameter into mm. We can find radius and convert it into it's SI unit.

i.e Radius (r) = 4/2 mm = 2 * 10⁻³ m

We know the formula that Pressure inside a rain drop is given as:

P = P₀ + 2T/r

where, P = Pressure inside a rain drop , T = surface tension

and r is radius , P₀ = atmospheric Pressure

here, P₀ = 1.013 * 10⁵ N/m²

Substituting the values,

P = 1.013 * 10⁵ * ( 2*0.072) / (2 * 10⁻³)

P = 1.01372 * 10⁵ Pa

Therefore, Pressure inside the raindrop is 1.01372 * 10⁵ Pa