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1
Answer:
b^2 - ( 2a^2 + 3c^2 + 2(2a)(3c) )
b^2 - ( 2a + 3c )^2
( b + 2a + 3c )( b - 2a - 3c)
Hope this will help you
Answered by
2
Step-by-step explanation:
b^2-(2a^2+3c^2+2(2a) (3c) )
b^2-(2a+3c) 2
(b+2a+3c) (b-2a-3c)
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