Math, asked by bhoomikadwivedi13, 8 months ago

solve:
b {}^{2}  - 12ac - 4a {}^{2}  - 9c {}^{2}

Answers

Answered by alphazz0123
1

Answer:

b^2 - ( 2a^2 + 3c^2 + 2(2a)(3c) )

b^2 - ( 2a + 3c )^2

( b + 2a + 3c )( b - 2a - 3c)

Hope this will help you

Answered by Nirmitaverma147
2

Step-by-step explanation:

b^2-(2a^2+3c^2+2(2a) (3c) )

b^2-(2a+3c) 2

(b+2a+3c) (b-2a-3c)

Similar questions