Question

A random sample of 5 gearboxes is selected from the shop floor of an automobile company. The proportion defective gearbox based on a comprehensive pilot study is 0.08. What is the probability of 2 or more defectives?

Answer 1

Answer:

0.99981

Step-by-step explanation:

We will take this as a binomial distribution.

The probabilities are as follows:

P(defective) = 0.08

P(not defective) = 1 - 0.08 = 0.92

n = 5 = 1 , 2 , 3 , 4 ,5

We want probability that the defective balls are 2 or more.

The distribution is :

P(X = x) = n!/x!(n - x)!  × Pˣ × (1 - p)ⁿ⁻ˣ

p = 0.92

1 - p = 0.08

P(2 or more are defective) = 1 - P(1 is not defective)

Now we want :

p(x = 1)

Doing the substitution we have :

= 1 - { 5!/1!(5 - 1)! × 0.92 × (0.08)⁵⁻¹}

= 1 - 0.000188416

= 0.99981

Answer 2

Answer:

Step-by-step explanation:what is the answer of (0.83⁵)