A random sample of size 775 is drawn from a large population. The population standard deviation is 8.7. The sample mean is 81.5. Find a 99% confidence interval for the population mean, . Round your answers to the nearest tenth.
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Step-by-step explanation:
Given A random sample of size 775 is drawn from a large population. The population standard deviation is 8.7. The sample mean is 81.5. Find a 99% confidence interval for the population mean
- So for C % confidence interval,
- n will be the sample size
- So σ will be the population standard deviation.
- So X bar is the sample mean
- Now
- Sample size is n = 775
- So population standard deviation σ = 8.7
- Sample Mean is X bar = 81.5
- So the critical value for a 99% confidence level is z = 2.576
- So we need to find 99% confidence level for the population mean.
- So we have μ = X bar + - Z . σ / √n
- = 81.5 + - 2.576 x 8.7 / √775
- = 81.5 + - 0.8052
- So we have two values.
- One is 81.5 - 0.8052
- = 80.6948
- = 80.7
- Another is 81.5 + 0.8052
- = 82.3052
- = 82.3
- So the 99% confidence for the population mean will be
- 80.7 < μ < 82.3
Reference link will be
https://brainly.in/question/7260437
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