Math, asked by s795026, 2 months ago

A random sample of size 775 is drawn from a large population. The population standard deviation is 8.7. The sample mean is 81.5. Find a 99% confidence interval for the population mean, . Round your answers to the nearest tenth.

Answers

Answered by knjroopa
0

Step-by-step explanation:

Given A random sample of size 775 is drawn from a large population. The population standard deviation is 8.7. The sample mean is 81.5. Find a 99% confidence interval for the population mean

  • So for C % confidence interval,
  • n will be the sample size
  • So σ will be the population standard deviation.
  • So X bar is the sample mean
  • Now  
  • Sample size is n = 775
  • So population standard deviation σ = 8.7
  • Sample Mean is X bar = 81.5
  • So the critical value for a 99% confidence level is z = 2.576
  • So we need to find 99% confidence level for the population mean.
  • So we have μ = X bar + - Z . σ / √n
  •                       = 81.5 + - 2.576 x 8.7 / √775
  •                      = 81.5 + - 0.8052
  • So we have two values.
  •        One is 81.5 - 0.8052
  •                    = 80.6948
  •                     = 80.7
  •     Another is 81.5 + 0.8052
  •                      = 82.3052
  •                      = 82.3
  • So the 99% confidence for the population mean will be
  •             80.7 < μ < 82.3

Reference link will be

https://brainly.in/question/7260437

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