Question

A random variable X has binomial distribution with n = 6 and p = 0.2 then variance of X is
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Answer 1

Answer:

The mean of the distribution (μx) is equal to n * P .

The variance (σ2x) is n * P * ( 1 - P ).

The standard deviation (σx) is sqrt[ n * P * ( 1 - P ) ].

Answer 2

The variance of X is 0.96

Given :

A random variable X has binomial distribution with n = 6 and p = 0.2

To find :

The variance of X

Solution :

Step 1 of 2 :

Write down the given data

A random variable X has binomial distribution with n = 6 and p = 0.2

Step 2 of 2 :

Find variance of X

The variance of X

$\sf = npq$

$\sf = np(1 - p)$

$\sf = 6 \times 0.2 \times (1 - 0.2)$

$\sf = 1.2 \times 0.8$

$\sf = 0.96$

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