Question

a ratio of maximum height and range of projectile projected with 50 m/s at angle of 45° is​

Answer 1

Answer:

1:4

Explanation:

formula used,

• maximum height=

u square sin square theta/2g

• range=

u square sin 2 theta/g

therefore,

maximum height /range=

( u square sin square theta / 2g) /

(u square sin 2 theta/g)

= (sin 45) /

4(cos 45)

= (tan45) /

4

= 1/4

=1:4