Question

A ray of light coming from (2,23–√)(2,23) is incidentat an angle30∘30∘ on the line x=1x=1 at the point A. The ray gets reflected on the line x=1x=1 and meets xx axis at a point BB. Then the line AB passes through the point​

Answer 1

Answer:let m be the gradient of the reflected say.

The angle betweenx=1 and x+y=1 is 45  

0

.

So the angle between the reflected ray and x+y=1 is also 45  

0

 

⇒  

1−m

m−(−1)

​  

=tan45  

0

=1

⇒m+1=1−1⇒m=0

So the equation of the reflected ray is y=0.

Step-by-step explanation: