A ray of light is incidence at an angle 52degree on the face of an equilateral prism and gets deviate through 34degree find the angle of emergence
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Ans. A=600 , δm=300
i = e = ¾ A = 450 ,
as A + δ = i + e
60 + δ = 45 + 45
or δ = 300
Refractive index,
m = sin a+δm /2 /sin A/2 = sin 600+300/2 / sin 600/2
= sin 450/sin300 = 1/√2 / ½ = √2 = 1.414
i = e = ¾ A = 450 ,
as A + δ = i + e
60 + δ = 45 + 45
or δ = 300
Refractive index,
m = sin a+δm /2 /sin A/2 = sin 600+300/2 / sin 600/2
= sin 450/sin300 = 1/√2 / ½ = √2 = 1.414
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