please answer it the 7 question in the photo
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Let 2angleA = 3angleB = 6angleC = k. Then,
angleA = k/2 ; angleB = k/3 ; angleC = k/6
Since, angleA + angleB + angleC = 180° ( as sum of all angles of a triangle is 180 )
k/2 + k/3 + k/6 = 180°
6k/6 = 180
k = 180°
angleA = 180/2 = 90°
angleB = 180/3 = 60°
angleC = 180/6 = 30°
Let 2angleA = 3angleB = 6angleC = k. Then,
angleA = k/2 ; angleB = k/3 ; angleC = k/6
Since, angleA + angleB + angleC = 180° ( as sum of all angles of a triangle is 180 )
k/2 + k/3 + k/6 = 180°
6k/6 = 180
k = 180°
angleA = 180/2 = 90°
angleB = 180/3 = 60°
angleC = 180/6 = 30°
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