a ray of light is incident normally one of the refrective surface of a prism. the angle of prism is 30.find the angle of deviation for the ray of light . given refrective index is 2
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Since the ray was incident normally on the surface, angle of incidence is 0, angle of refraction is 0, and also the angle of deviation is 0
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A = 30°
μ = √2
(For thin prisms) We have the relation δ = (μ − 1)A
= (√2 − 1) x 30°
= 12.4°
The option which is close to this is (D).
μ = √2
(For thin prisms) We have the relation δ = (μ − 1)A
= (√2 − 1) x 30°
= 12.4°
The option which is close to this is (D).
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