A ray of light travelling in air falls on the suraface of ractanglular slab of a plastic material whose refractive index is 1.6 if the incident ray makes an angle of 53 with the normal .find the angle made by the refracted ray with the normal
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A ray of light traveling in air falls on the surface of a rectangular slab of a plastic material whose refractive index is 1.6. If the incident ray makes an angle of 53° with the normal, find the angle made by the refracted ray with the normal (sin 53° = 4/5).
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We know that refractive index of air is 1.
Here the incidence angle is (I)=53°
Using Snell's law
refractive index in air sin I =refractive index in glass sin r
sin 53°=1.6sin r
4/5=1.6sin r
=4/5×1.6
=1/2sin=30°
THAT ANSWER GIVEN BY GAURAV YADAV
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