Question

A ray of light travelling in air falls on the surface of a transparent material at an angle of 45 degree with the normal. It bends 15 degree after refraction. Find the refractive index of the material.

Answer 1

Incident angle=45
angle of refraction = 15
if refractive index of air is 1, then
RI of the transparent medium = 1 + incident angle/angle of refraction
=1+ 15/45
=1+1/3
=1+0.333
=1.333
Refractive index of the transparent medium is 1.333

Answer 2

Given:

Angle of incident

= 45

Angle of refraction

= 15

To Find:

The refractive index of the material = ?

Solution:

As we know,

⇒  $RI \ of \ the\ transparent \ medium = 1 + \frac{Angle \ of \ incident}{Angle \ of \ refraction}$

On substituting the given values, we get

⇒                                                     $=1+\frac{15}{45}$

⇒                                                     $=1+0.333$

⇒                                                     $=1.333$

So that the refractive index will be "1.333".