Question

A reaction 2a(g) - b. + 3c. Hask = 0.98 hr-1 initial pressure of a is 3 p, and that of band after time 't' the total pressure due to products is p. The value of kt for the reaction is

Answer 1

Answer:

Explanation:

the value of kt for the reaction is = 2a- b

Answer 2

The equilibrium constant for the reaction is  K =   (0.75)^3  (0.25)  / (0.50)^ 2  (0.75)  

Explanation:

The reaction, 2A(g)+B(g)⇌3C(g)+D(g) is begun with the concentrations of A and B both at an initial value of 1.00 M. When equilibrium is reached, the concentration of D is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression?

Solution:

The reaction:

                             2A(g)+B(g)⇌3C(g)+D(g)

Initially                 1 1 0 0

At Equilibrium. 1  - 2x = 1- 0.5 1 - x =1 -0.25 3x = 0.75 x = 0.25

K=   [C]  3 [D]  / [A]  2  [B]  

K =   (0.75)^3  (0.25)  / (0.50)^ 2  (0.75)

Thus the equilibrium constant for the reaction is  K =   (0.75)^3  (0.25)  / (0.50)^ 2  (0.75)

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