Question

A reaction between solid sulfur and oxygen produces sulfur dioxide. What is the percent yield for a reaction if you predicted the formation of 680g of sulphur dioxide and actually recovered only 384g?

Answer 1

Answer:

56.47%

Explanation:

In this question, we are given;

Theoretical yield of sulfur dioxide as 680 g

Actual yield of sulfur dioxide as 384 g

We are required to calculate the percent yield for the reaction;

We need to know how percent yield is calculated;

% yield = (Actual yield ÷ Theoretical yield) × 100%

Therefore;

In this case;

% yield = (384 g ÷ 680 g) × 100%

           = 56.47%

Thus, the percent yield for the reaction is 56.47%